To solve this problem, we need to compute the sum of squares of the first n natural numbers. The original code had a few issues that needed correction, including variable shadowing, incorrect range, and indentation errors.

Approach

1. Avoid Variable Shadowing: The variable name sum is a built-in function in Python, so we use total instead to prevent shadowing.
2. Correct Range: To include the nth term, we use range(1, n+1) since Python's range is exclusive of the upper bound.
3. Fix Indentation: The if __name__ == "__main__": line should be at the top level (unindented), and the print statement should be indented under it.

Corrected Code

def sum_of_squares(n):
    total = 0
    for i in range(1, n + 1):
        total += i * i
    return total

if __name__ == "__main__":
    print(sum_of_squares(10))

Explanation

• Function Definition: The sum_of_squares function initializes total to 0, then iterates over each number from 1 to n (inclusive). For each number i, it adds i*i to total.
• Main Block: The main block calls sum_of_squares(10) and prints the result, which is the sum of squares from 1 to 10 (1² + 2² + ... + 10² = 385).

This approach efficiently computes the desired sum with a time complexity of O(n) and space complexity of O(1). The corrections ensure the code is correct, readable, and follows Python best practices.

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